Physics Homework: find the speed of the block after it has moved?

Q) 19 kg block initially at rest pulled to the right along a horizontal surface by a constant, horizontal force of 16.1 N. the coefficient of kinetic friction is 0.145. the acceleration of gravity is 9.8 m/s^2.find the speed of the block after it has moved 3.35 m.

Sol:

As per the concept that the work done by the force is equal to the Kinetic energy of the block, we have

u*(mg)*s=1/2mv² where work done= u*(mg)*s, u=0.145,m=19kg,g=9.8m/s², s=3.35m

Therefore by substituting the values in the above equation, we get,

0.145*9.8*3.35=0.5* v²

Hence Speed of the block after it has moved 3.35m is,

V= 3.086m/s