Q)Kc = 2.6 × 10^8 at 825 K
for the reaction
2H2(g) + S2(g) <===> 2H2S(g)
The equilibrium concentration of H2 is 0.0020 M and that of S2 is 0.0010 M. What is the equilibrium concentration of H2S?
1. 0.0010 M
2. 1.02 M
3. 10 M
4. 0.10 M
2H2(g) + S2(g) <===> 2H2S(g)
The equilibrium concentration of H2 is 0.0020 M and that of S2 is 0.0010 M. What is the equilibrium concentration of H2S?
1. 0.0010 M
2. 1.02 M
3. 10 M
4. 0.10 M
Sol:
Kc = [H2S]2/[H2]2*[S2]
2.6*108 = [H2S]2/[0.002]2[0.001]
Hence equilibrium concentration of [H2S]= 1.02M
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