Assignment Help: Calculate the resistivity of the wire material..

Q) A wire 4.00 m long and 6.00 mm in diameter has a resistance of 15.0Ω. A
potential difference of 23.0 V is applied between the ends. (a) What is the current in
the wire? (b) What is the magnitude of the current density? (c) Calculate the resistivity
of the wire material. (d) Attempt to use a Table in the chapter to identify the material.

Sol:

Given that L=4m, r=d/2=3mm, V=23V, I =? , Current density J=? , Resistivity =?

From ohms law, we have V=IR

a) Current I = V/R

          =23/15=1.53A

b) Current density, J = Conductivity*Electric field,......................................................................................................................................

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