Think and Answer Assignments: Minicase IV Household Wireless page....

Q)Your sister is building a new two story house which measures 50 feet long by 30 feet wide and wants to network her family’s three computers together. She and her husband are both consultants and work out of their home in the evenings and a few days a month.  Each has a separate office with a computer, plus a laptop from the office that they occasionally use. The kids also have a computer in their playroom. They have several options for networking their home:

a) Wire the two offices and playroom with Ethernet cat5e and put in a 100Base-T switch.

b) Install one Wi-Fi access point ($85) and put Wi-Fi cards in the three computers (the laptops already have Wi-Fi)

c) Any combination of these options

There are many possible solutions to this problem.  What would you recommend, considering their current hardware configuration as well as potential expansion? Justify your recommendation.           

Sol:

The best possible solution is to go for installation of Wi-Fi access points followed by installation of Wi-Fi cards for the desktop computers. Anyways laptops will definitely have Wi-Fi inbuilt so there is no need for separate installation of the cards in laptops. The reason behind this is looking at the future definitely the desktops are getting replaced by laptops. Also laptops are portable, which means we can carry them any where we need but if they are connected to some network cables then we will not be able to access the network wherever we carry the laptops. Also in case of desktops if we place it in 1st floor but tomorrow we need it in the last floor then there is need to work on the network connectivity in it only labor is involved in shifting but network connectivity is always there since it is independent of the location within the office campus or two story house limits. Hence the recommendation here is to go for Wi-Fi connection.

Read and Answer: The International Centre for Radio Astronomy Research...

1) The International Centre for Radio Astronomy Research

The CSIRO Wireless LAN story

CSIRO’s wireless LAN is one of the most leading technologies, and also most of you are already aware of the story. The technology lies at the heart of the most popular way of connecting computers without wires which is now known as wireless LAN. CSIRO has reminded very important and also lucrative always in terms of getting things done in the better manner. The Science and technology Industry Endowment Fund launched has been made possible by the success of CSIRO’s wireless LAN technology. Hence we can pay a particular tribute to everyone those who have made the Science and Industry Endowment Fund possible by creating CSIRO’s wireless local area network technology. Recently, CSIRO has sharpened its focus very well on Australia’s greatest opportunities and challenges through its National Research Flagships. CSIRO’s wireless LAN technology ranks as a major achievement in Australia, and it would be great enough to see significant objects related to the wireless LAN story which is being researched these days.

Questions:

a) Name the inventers of CSIRO WLAN?

b) Commercial board of CSIRO is chaired by?

c) Where was the CSIRO research carried out?

d) In which place in Australia the CSIRO WLAN was launched?

Sol:

a) Terry Percival, John Deane, Graham Daniels, Diet Ostry and John O’Sullivan.

b) Dr Terry Cutler.

c) In Australia.

d) National Museum of Australia.

Looking for the solutions of few mathematics questions?

a) ABC' + B C' D' + B C + C' D = B + C' D

Sol:

LHS = (ABC’+BC)+ (BC’D’+C’D)

       =B(C+C’A) +C’ (D+D’B)

       =B(C+A) +C’ (D+B)

       =AB+BC+C’D+C’B

      =AB+C’D+B (C+C’)                //C+C’=1

      =AB+C’D+B

      =B (1+A) +C’D                        //1+A=1

      =B+C’D

      =RHS

b) WY + W' Y Z' + WXZ + W' X Y' = WY + W' X Z' + X' Y Z' + X Y' Z

Sol:

RHS=wy + w’xz’ + x’yz’ + xy’z

        =WY(1+XZ)+ w’xz’(Y+Y’)+ x’yz’ (W+W’)+ xy’z(W+W’)         //Y+Y’=W+W’=1+XZ=1

        = wy + wxyz + w’xyz’ + w’xy’z’ +wx’yz’ + w’x’yz’ + wxy’z + w’xy’z

        =wy + w’xyz’ + w’x’yz’ + wxyz +wxy’z + w’xy’z + w’xy’z’ + wx’yz’

        =wy + wx’yz’ + w’yz’(x + x’) + wxz(y + y’)+w’xy’(z + z’)

        =wy(1 + x’z’) + w’yz’ + wxz + w’xy’

        = WY + W' Y Z' + WXZ + W' X Y'

        =LHS

c) A D' + A' B + C'D + B'C = (A' + B' + C' + D')(A + B + C + D') = AC’+A’B +B‘C + D’

Sol:

RHS=(A' + B' + C' + D')(A + B + C + D')

        =A’A+A’B+A’C+A’D’+B’A+B’B+B’C+B’D’+C’A+C’B+C’C+C’D’+D’A+D’B+D’C+D’D’

        =A’B+A’C+A’D’+B’A+B’C+B’D’+C’A+C’B+C’D’+D’A+D’B+D’C+D’   //AA’=0; D’D’=D’

        = AC’+A’B +B‘C + D’+ A’C (B+B’) + B’A (C+C’) + C’B (A+A’)    //A+A’=1

        = AC’ (1 + B’ + B) + A’B (1 + C’ + C) +B’C(1 + A + A’) + D’    //1+A=1

        = AC’+A’B +B‘C + D’

        =LHS

Chemistry Homework Help: How many atoms of helium gas are required to fill a balloon to diameter..

Q)The molecular mass of helium is 4 g/mol, the Boltzmann’s constant is 1.38066 ×
10−23 J/K, the universal gas constant is 8.31451 J/K · mol, and Avogadro’s number
is 6.02214 × 1023 1/mol. Given: 1 atm = 101300 Pa.
How many atoms of helium gas are required to fill a balloon to diameter 30 cm at 12◦C and 0.95 atm?

Sol:

PV = nRT
n = PV/RT
Number of atoms (N)= Avogadro's number (A) * n
N = A*n = A*(PV/RT)
P = 0.95 * 101300 Pa
P = 96235 Pa
V = (4/3) pi R^3
R = 0.15 m
V = (4/3) pi (0.15 m)^3
V = 0.01414 m^3
T = 273.15 + 12
T = 285.15 K

N = 6.02214 x 10^23 atoms/mole * (96235 Pa * 0.01414 m^3) / (8.31451 J/K-mol * 285.15 K)
N = 3.456 x 10^23 atoms

Chemistry Assignment Help: What is the equilibrium concentration of H2S...

Q)Kc = 2.6 × 10^8 at 825 K for the reaction

2H2(g) + S2(g) <===> 2H2S(g)

The equilibrium concentration of H2 is 0.0020 M and that of S2 is 0.0010 M. What is the equilibrium concentration of H2S?

1. 0.0010 M
2. 1.02 M
3. 10 M
4. 0.10 M

Sol:

K_c = [H2S]²/[H2]²*[S2]

2.6*10⁸ = [H2S]²/[0.002]²[0.001]

Hence equilibrium concentration of [H2S]= 1.02M

Chemistry Homework Help: what is the equilibrium concentration of...

Kc = 9.7 at 900 K for the reaction

NH3(g) + H2S(g) ---> NH4HS(s) .

If the initial concentrations of NH3(g) and H2S(g) are 2.0 M, what is the equilibrium concentration of NH3(g)?

1. 0.20 M
2. 1.7 M
3. 0.10 M
4. 0.32 M
5. 1.9 M

Sol:

K_c = [NH4HS]/[ NH3]*[ H2S]

At equilibrium the concentration of NH3 will be (2-x)

9.7=1/(2-x)²

Hence, 2-x = 0.32M

Physics Homework Help: Compare the kinetic energy of an...

Q) Compare the kinetic energy of an 900 kg car travelling at 30 m/s, and a 1,800 kg car at the same speed.

 Sol:

Kinetic energy is given by, KE = 1/2mv²

Where ‘m’ is the mass, ‘v’ is the velocity.

Case1:

Given m=900kg, v=30m/s

(KE) ₁= 0.5*900*30²=405000Joules

Case2:

Given m=1800kg,v=30m/s

(KE) ₂= 0.5*1800*30²=810000Joules

Therefore, (KE) ₂ = 2(KE) ₁

Write-Ups: Profiles can be defined to limit resource usage...

Q)Profiles are used to limit resources and implement password policies. Oracle implements password checking by defining a function to the database at login time. The default function provided by Oracle is implemented in a file.

Profiles can be defined to limit resource usage.

Why would you want to limit resource usage at all?

I would like the answer in about 150 words.

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Write-Ups: You have just been hired as an information security engineer for a large multi-international corporation...

Q) You have just been hired as an information security engineer for a large multi-international corporation. Unfortunately your company has suffered from multiple security breaches that have threaten the public's trust that their confidential data and financial assets are private and secured. Credit card information was compromised by an attacked who infiltrated the network through an vulnerable wireless connection within the organization and the other breach was an inside job, where personal data was stolen because of weak access control policies within the organization which allowed an unauthorized individual access to valuable data. Your job is to develop a risk management policy that addresses the two security breaches and how to mitigate these risks.

This assignment requires 2 to 3 pages in length (500 words minimum), based upon the APA style of writing.

Use transition words, thesis statement, Introduction, Body, Conclusion and Reference Page with at least two references. Double spaced Arial 12 Font.

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Homework Help: What is the instantaneous power delivered by the...

Q)A single constant force 25.1 N acts on a particle of mass 6.53 kg. The particle starts at rest at t = 0.
What is the instantaneous power delivered  by the force at t = 4.31 s?

Answer in units of W.

Sol:

Force, F=mass(m)*acceleration(a)

a= 25.1/6.53

 = 3.84m/s²

Instantaneous power delivered by the force at time t=4.31sec is given by,

P(t)= F(t)*V(t)

V(t)=U(t)+at

At t=4.31sec, U(t)=0

V(t)=3.84*4.31= 16.55m/s

Hence, P(t)= 25.1*16.55

           = 415.4W

Homework Help: What is the gauge pressure in the tire after a ride on a hot day when the tire....

The tire on a bicycle is filled with air to a gauge pressure of 647 kPa at 20◦C. What is the gauge pressure in the tire after a ride on a hot day when the tire air tempera- ture is 69◦C? (Assume constant volume and a constant atmospheric pressure of 101.3 kPa.)
Answer in units of kPa.

Sol:
Here the formulae used is:

P1V1=n1RT1
P2V2=n2RT2

Where P1=po+pg
P1=101.3kPa + 647kPa= 748.3kPa
n1=n2
also given that V1=V2.
Hence, P1/T1=nR/V=P2/T2
P1/P2=T1/T2
or
P2=(P1*T2)/T1 = (748.3 *(273+69))/(273+20)
P2=748.3kPa(342K/293K)= 748.3kPa * (1.167)=873.44kPa

Homework Help: what is the new pressure in the tank?

Gas is confined in a tank at a pressure of 10 atm and a temperature of 13◦C. If 38 percent of the gas is withdrawn and the temperature iGas is confined in a tank at a pressure of 10 atm and a temperature of 13◦C. If 38 percent of the gas is withdrawn and the temperature is raised to 70◦C, what is the new pressure in the tank? Answer in units of atm.s raised to 70◦C, what is the new pressure in the tank?
Answer in units of atm.

Sol:

Here we will make use of the formulae:

P2 = P1*(V1/V2)*(T2/T1), where V2 = 0.62(V1), T1= 13+273= 286K

T2= 70+273= 343

P2 = 10*1.6129*343/286 = 19.34atm

Homework Help: what is canonical commutation of..

Q)  what is canonical commutation of [p^2,q^2]

Sol:

Hence canonical computation of [p², q²] = (2ip)*(-2iq)

                                        = 4pq, since i²= -1

Database Assignment Help: Execute your script to create the new user...

#User roles
You need to create a new user named ASSOCDBA1 and a new ROLE named JRDBA1 that can be used for an assistant DBA. You want the new role to contain the DBA role that the SYSTEM user has with ADMIN OPTION (when it pertains to the current SYSTEM user setting). You also want the new role to be password-protected with a password of MJOAG2T. Once the role is created, assign the role to the new user ASSOCDBA1, but do not make it the default role.

Execute your script to create the new user, the new ROLE, assign privileges to the role, and assignment of the ROLE to the user.

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SQL Homework Help: Could you write the SQL commands that would implement this profile...

#User profiles
Your company has hired several new people for a new department project in your regions. This department will have some different requirements from regular works, and the DBA wants to ensure that the new hires will not be getting stepped on by current users in the database and vise versa. To help insulate the new hires, it has been decided to create a specific profile for them. The profile name will be NEWREG1 and it will need to have the following properties:

* After three login attempts, the account should be locked.
* The password should expire after 30 days.
* The same password should not be reused again for at 31 days.
* The account should have a grace period of five days to change an expired password.
* Each user can have 3 concurrent sessions open.

Could you write the SQL commands that would implement this profile. Next, write the query that would list the profile, the profile resource name, and the limit value for the new profile.

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Homework Help: The coefficient of performance for refrigerators....

Q) The coefficient of performance for refrigerators is defined as K = qc / w. It is also known as Tcold / Thot - Tcold.

What happens to K reversible as Tc (temp cold) goes to 0k?

Sol:

K = T_cold/(T_hot-T_cold)

K reversible means 1/K

Hence 1/K= (T_hot-T_cold)/ T_cold

              = (T_hot/ T_cold)-( T_cold/ T_cold)

         =  (T_hot/ T_cold)- 1

By neglecting 1, which is a small value, we get

1/K directly proportional to 1/ T_cold

Hence as T_cold goes to 0k, K reversible tends to infinity, a very large value.

Assignment Help: Derive an expression for link utilization...

Q) Derive an expression for link utilization U of a data link that uses the sliding-window flow control and returns an ACK for every OTHER frame received. Assume error free transmission. Link length is d, propagation velocity is v, frame size is L, and window size is W.

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HomeWork Help: Count back from the secondary after the last frame? Assume error-free operation..

Q) Assume that the primary HDLC station in NRM has sent six I-frames to a secondary. The primary’s N(S) count was three(011 binary) prior to sending the six frames. If the poll bits are in the sixth frame, what will be the N(R) count back from the secondary after the last frame? Assume error-free operation.

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HomeWork Help: What is the current in the bulb..

Q) A 100 W lightbulb is plugged into a standard 120 V outlet. (a) How much does it
cost per 31-day month to leave the light turned continuously? Assume electrical
energy costs US$0.06/kWh. (b) What is the resistance of the bulb? (c) What is the current in the bulb?

Sol:

First let us find the energy used in 31 days is(in kWh) and then let go for calculating the cost.

a) U = P * t = 0.100kW * 31days * 24hrs/day

       = 74.4kWh

Cost per 31 day month = 74.4kW h * $0.06/kW h

  = $4.464

b) The resistance of the bulb is given by,

P = V²/R

R = V²/P

  = (120V)²/100W

=144Ω

c) The current in the bulb is given by,

P = VI

I = P/V

     = 100W/120V

 = 0.833 A

Assignment Help: How much thermal energy is produced in..

Q) A 1250 W radiant heater is constructed to operate at 115 V. (a) What is the current in
the heater when the unit is operating? (b) What is the resistance of the heating coil? (c)
How much thermal energy is produced in 1.0 h?

Sol:

a) We can calculate the current ‘I’ from the power and voltage.

P = IV

I = P/V

= 1250/115

=10.87A

b) We can calculate the Resistance ‘R’ from the Voltage and power

P = V²/R

R = V²/P

= (115)²/1250

=10.58ohms

c) Thermal energy ‘U’ produced in 1 hr=3600secs is given by,

U = P * t =1250 *3600 = 4.5 *10⁶J