Q)A single constant force 25.1 N acts on a particle of mass 6.53
kg. The particle starts at rest at t = 0.
What is the instantaneous power delivered by the force at t = 4.31 s?
What is the instantaneous power delivered by the force at t = 4.31 s?
Answer
in units of W.
Sol:
Force, F=mass(m)*acceleration(a)
a= 25.1/6.53
= 3.84m/s2
Instantaneous power delivered by the force at time t=4.31sec is
given by,
P(t)= F(t)*V(t)
V(t)=U(t)+at
At t=4.31sec, U(t)=0
V(t)=3.84*4.31= 16.55m/s
Hence, P(t)= 25.1*16.55
=
415.4W
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