Kc = 9.7 at 900 K for the
reaction
NH3(g) + H2S(g) ---> NH4HS(s) .
If the initial concentrations of NH3(g) and H2S(g) are 2.0 M, what is the equilibrium concentration of NH3(g)?
1. 0.20 M
2. 1.7 M
3. 0.10 M
4. 0.32 M
5. 1.9 M
NH3(g) + H2S(g) ---> NH4HS(s) .
If the initial concentrations of NH3(g) and H2S(g) are 2.0 M, what is the equilibrium concentration of NH3(g)?
1. 0.20 M
2. 1.7 M
3. 0.10 M
4. 0.32 M
5. 1.9 M
Sol:
Kc = [NH4HS]/[ NH3]*[ H2S]
At equilibrium the concentration of NH3 will be
(2-x)
9.7=1/(2-x)2
Hence, 2-x =
0.32M
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