Showing posts with label Chemistry. Show all posts
Showing posts with label Chemistry. Show all posts

Wednesday, 26 November 2014

Read and Answer: The International Centre for Radio Astronomy Research...

1) The International Centre for Radio Astronomy Research
Sol:
The International Centre for Radio Astronomy Research is a collaborative centre placed in Perth, Western Australia. They are already achieving research excellence in both astronomical science and engineering. The International Centre for Radio Astronomy Research has grown steadily from its launch in September 2009. An equal joint venture between The University of Western Australia and Curtin University, International Centre for Radio Astronomy Research has strong support from the West Australian as well as Australian governments and is working very closely with industry and research partners in Australia and in the entire world. Wireless internet (WIFI) inventor honored Curtin University has been recognized as Dr John O’Sullivan’s ground breaking work in astronomy and wireless technologies by bestowing John with an Honorary Science Doctorate. The latest telescope puts focus on high school discoveries where a new internet telescope was launched by State Education Minister Dr Elizabeth Constable at The Western University of Australia. Also
Sky Noise and Sensitivity Studies of Array Configurations and Antenna Elements were done for the Low-Frequency Band of the SKA.

Questions:
a) What is WIFI?
b) Expand ICRAR?
c) Internet telescope was launched by whom?
d) Who invented wireless internet?

Sol:
a) Wireless internet/wireless LAN.
b) International Centre for Radio Astronomy Research.
c) Dr. Elizabeth.

d) Dr John O’Sullivan

Read and Answer: Passive acoustic techniques to study sound producing fish species...

1) Passive acoustic techniques to study sound producing fish species
A wide variety of taxa fish produce sound. The behavior of Sound production gives an opportunity to study and analyze various aspects of fish biology, such as habitat selection and spawning behavior, in a very non-invasive manner. Passive acoustics is an active area of research called ichthyologic research. However, fish bio-acousticians have not published their research details in the fisheries literature. Therefore, fisheries scientists may not be aware of progress being made in this field completely or the potential uses for acoustic techniques passively. The physiological, behavioral and evolutionary aspects of sound production by fishes generally investigate the patterns of research publication on sound production by the fish and also review the literature which is based on the passive acoustic methods application to the research of fisheries and finally predicts and tells different ways of passive acoustic surveys which is being designed to optimize the quality and quantity of information obtained. Passive acoustic methods can be definitely attractive as well as alternative or it may supplement to the other traditional fisheries based on assessment techniques since they are non-invasive, and also can be conducted at low cost, which covers a large study area at temporal resolution and high spatial.

Questions:
a) Name the fish which produces sound?
b) Which are the three aspects of sound production?
c) Which acoustic method can be attractive?
d) What can be the Passive acoustic methods?
Sol:

  1. Taxa
  2. Physiological, behavioral and evolutionary aspects.
  3. Passive acoustic method.
  4. non-invasive

Read and Answer: The International Centre for Radio Astronomy Research...

1) The International Centre for Radio Astronomy Research
The CSIRO Wireless LAN story
CSIRO’s wireless LAN is one of the most leading technologies, and also most of you are already aware of the story. The technology lies at the heart of the most popular way of connecting computers without wires which is now known as wireless LAN. CSIRO has reminded very important and also lucrative always in terms of getting things done in the better manner. The Science and technology Industry Endowment Fund launched has been made possible by the success of CSIRO’s wireless LAN technology. Hence we can pay a particular tribute to everyone those who have made the Science and Industry Endowment Fund possible by creating CSIRO’s wireless local area network technology. Recently, CSIRO has sharpened its focus very well on Australia’s greatest opportunities and challenges through its National Research Flagships. CSIRO’s wireless LAN technology ranks as a major achievement in Australia, and it would be great enough to see significant objects related to the wireless LAN story which is being researched these days.

Questions:
a) Name the inventers of CSIRO WLAN?
b) Commercial board of CSIRO is chaired by?
c) Where was the CSIRO research carried out?
d) In which place in Australia the CSIRO WLAN was launched?

Sol:
a) Terry Percival, John Deane, Graham Daniels, Diet Ostry and John O’Sullivan.
b) Dr Terry Cutler.
c) In Australia.

d) National Museum of Australia.

Tuesday, 25 November 2014

The total number of partitions of a k-element...

Q) The total number of partitions of a k-element
   set is denoted by B (k) and is called the k-th Bell number.
    Thus B (1) = 1and B (2) = 2.
   Need to find B (k) for k = 4, 5, 6.
Sol:


We know that,

Where,

Is the Binomial Coefficient.

It is given by:



It’s given that B (0) =1; B (1) =1; B (2) =2
Hence for n=3, from the first formulae
B (3) =C (2, K) B (K) where K=0 to n-1
B(3)=C(2,0)B(0)+ C(2,1)B(1)+ C(2,2)B(2)
From the second formulae, C (2, 0) =2! /0! (2-0) = 1
C (2, 1) =2; C (2, 2) =1
Hence,
B (3) =1*1+2*1+1*2=5
For n=4,
B(4)= C(3,0)B(0)+ C(3,1)B(1)+ C(3,2)B(2) + C(3,3)B(3)
        = 1*1+3*1+3*2+1*5= 15
Similarly,
For n=5,
B (5) = 52
For n=6,
B (6) = 203

Assignment Help: Case Study on...

Case study:  Consider a 500 gallon tank that needs to be filled when the level goes below 25 gallons and will stop when the level goes above 475 gallons.

Control systems can be either open-loop or closed-loop; each one of them has their own advantages and problems.  For the system described above:


1)      Describe how you would implement it using an open-loop system

To be continued based on the request, please feel free to write to us from contact us form or comment over here!!!

Chemistry Homework Help: How much more soluble is...

(a) How much more soluble is AgCl in 1 Molar NH3 than in water?
(b) How much more soluble is CaSO4 in 1 Molar HNO3 than in water?


Sol:
1) A chloride solution of metal reacts with silver nitrate solution to produce a precipitate. The precipitate is soluble in Ammonia solution:
Actually, NH3 complexes silver to make Ag (NH3)2, and this reaction is favorable enough to make AgCl dissolve (but not the much more insoluble Agcl. Hence Agcl is soluble in 1 molar NH3 to some extent.
2Agcl + 4NH3 ==> 2Ag (NH3)2 + cl2

2) CaSO4 is infinitely much more soluble in 1 molar HNO3. The reason is that the CaSO4 (mostly insoluble in water) is converted to Ca (NO3)2 which is very much soluble in water. As a result calcium sulphate is infinitely very much soluble in nitric acid.

CaSO4 +2HNO3 ==> Ca(NO3)2 + H2SO4


Write-Ups Assignment Help: What is a little-know secret to the profitability of Amazon.com?

The below are few of the topics on which the write-ups of 300 to 500 words are expected:

1) What is a little-know secret to the profitability of Amazon.com?

2) Which of these characterized the strategies is the early days (and somewhat, still today) of electronic commerce?

3)Q)“Words carry the message. They would carry the same meanings with or without paragraphing. Therefore, paragraphing has no effect on communication.” Discuss your view of this statement and provide an example which supports your analysis. 

4)What is access matrix? For what purpose is access matrix used in general purpose OS?

4)Many people feel that the American government is out of touch with its public. Look at the branches of government and analyze this statement. 

Need an answer, Please comment on this post!!!

Homework Help: What is the rms speed of each helium atom...

Q)The molecular mass of helium is 4 g/mol, the Boltzmann’s constant is 1.38066 ×
10−23 J/K, the universal gas constant is 8.31451 J/K · mol, and Avogadro’s number
is 6.02214 × 1023 1/mol. Given: 1 atm = 101300 Pa.
What is the rms speed of each helium atom?
Answer in units of m/s.

Sol:
The average kinetic energy is given by:
KEatom = (PV)/N
Number of atoms (N)= Avogadro's number (A) * n
where N = A*n = A*(PV/RT)
N = 6.02214 x 10^23 atoms/mole * (96235 Pa * 0.01414 m^3) / (8.31451 J/K-mol * 285.15 K)
N = 3.456 x 10^23 atoms

KEatom = (96235*0.01414 /3.456 x 10^23 )J/atom

      = 3.94 X 10^-21 J/atom

KEa = (1/2) m v^2
m = (Molecular Mass (Mm) / A)
m = (0.004 kg/mole / 6.02214 x 10^23 atoms/mole)
m = 6.42 x 10^-27 kg/atom
v^2 = (2 KEa)/m
v = sqrt((2 KEa) / m)
v = sqrt((2 * 3.94 X 10^-21 J/atom) / 6.42 x 10^-27 kg/atom)
v = 1108 m/s


Monday, 24 November 2014

Homework Help: What is the average kinetic energy of each helium atom...

Q)The molecular mass of helium is 4 g/mol, the Boltzmann’s constant is 1.38066 ×
10−23 J/K, the universal gas constant is 8.31451 J/K · mol, and Avogadro’s number
is 6.02214 × 1023 1/mol. Given: 1 atm = 101300 Pa.
What is the average kinetic energy of each helium atom?
Answer in units of J.

Sol:
The average kinetic energy is given by:
KEatom = (PV)/N
Number of atoms (N)= Avogadro's number (A) * n
where N = A*n = A*(PV/RT)
N = 6.02214 x 10^23 atoms/mole * (96235 Pa * 0.01414 m^3) / (8.31451 J/K-mol * 285.15 K)
N = 3.456 x 10^23 atoms


KEatom = (96235*0.01414 /3.456 x 10^23 )J/atom

      = 3.94 X 10^-21 J/atom

Chemistry Homework Help: How many atoms of helium gas are required to fill a balloon to diameter..

Q)The molecular mass of helium is 4 g/mol, the Boltzmann’s constant is 1.38066 ×
10−23 J/K, the universal gas constant is 8.31451 J/K · mol, and Avogadro’s number
is 6.02214 × 1023 1/mol. Given: 1 atm = 101300 Pa.
How many atoms of helium gas are required to fill a balloon to diameter 30 cm at 12◦C and 0.95 atm?

Sol:

PV = nRT
n = PV/RT
Number of atoms (N)= Avogadro's number (A) * n
N = A*n = A*(PV/RT)
P = 0.95 * 101300 Pa
P = 96235 Pa
V = (4/3) pi R^3
R = 0.15 m
V = (4/3) pi (0.15 m)^3
V = 0.01414 m^3
T = 273.15 + 12
T = 285.15 K

N = 6.02214 x 10^23 atoms/mole * (96235 Pa * 0.01414 m^3) / (8.31451 J/K-mol * 285.15 K)
N = 3.456 x 10^23 atoms


Homework Help: What is the speed of the block when the spring has been compressed...

A block with a mass of 0.148kg is traveling at 8.4m/s on a horizontal,frictionless surface when it hits a spring with a spring constant of 722 N/m. What is the compression of the spring when the block has slowed to 3.9 m/s?What is the speed of the block when the spring has been compressed by 0.049m?

Looking for an answer to this question, then comment on this post!!!

Physics Assignment Help: How much work is done moving a...

Q)How much work is done moving a 2.5 kg book to a shelf 3.0 m high?

a.What is the potential energy of the book in #7 above?
b.If the book in #7 above, falls off the shelf, how much kinetic energy will it have when it hits the floor

Sol:
Work done = Force*displacement
Force=m*g=2.5*9.8=24.5N
Work done= 24.5*3=73.5Joules
a) Potential energy = work done= m*g*h= 73.5Joules
b) Kinetic energy when it hits the floor will be at t=0,
V=U + at=0+9.8*0=0
KE= ½*m*v2 = 0J


Chemistry Assignment Help: What is the equilibrium concentration of H2S...

Q)Kc = 2.6 × 10^8 at 825 K for the reaction

2H2(g) + S2(g) <===> 2H2S(g)

The equilibrium concentration of H2 is 0.0020 M and that of S2 is 0.0010 M. What is the equilibrium concentration of H2S?

1. 0.0010 M
2. 1.02 M
3. 10 M
4. 0.10 M

Sol:
Kc = [H2S]2/[H2]2*[S2]
2.6*108 = [H2S]2/[0.002]2[0.001]

Hence equilibrium concentration of [H2S]= 1.02M

Sunday, 23 November 2014

Chemistry Homework Help: what is the equilibrium concentration of...

Kc = 9.7 at 900 K for the reaction

NH3(g) + H2S(g) ---> NH4HS(s) .

If the initial concentrations of NH3(g) and H2S(g) are 2.0 M, what is the equilibrium concentration of NH3(g)?

1. 0.20 M
2. 1.7 M
3. 0.10 M
4. 0.32 M
5. 1.9 M


Sol:
Kc = [NH4HS]/[ NH3]*[ H2S]
At equilibrium the concentration of NH3 will be (2-x)
9.7=1/(2-x)2

Hence, 2-x = 0.32M

Homework Help: what is the new pressure in the tank?

Gas is confined in a tank at a pressure of 10 atm and a temperature of 13◦C. If 38 percent of the gas is withdrawn and the temperature iGas is confined in a tank at a pressure of 10 atm and a temperature of 13◦C. If 38 percent of the gas is withdrawn and the temperature is raised to 70◦C, what is the new pressure in the tank? Answer in units of atm.s raised to 70◦C, what is the new pressure in the tank?
Answer in units of atm.

Sol:
Here we will make use of the formulae:
P2 = P1*(V1/V2)*(T2/T1), where V2 = 0.62(V1), T1= 13+273= 286K
T2= 70+273= 343

P2 = 10*1.6129*343/286 = 19.34atm

Homework Help: what is canonical commutation of..

Q)  what is canonical commutation of [p^2,q^2]

Sol:


Hence canonical computation of [p2, q2] = (2ip)*(-2iq)
                                        = 4pq, since i2= -1



Homework Help: The coefficient of performance for refrigerators....

Q) The coefficient of performance for refrigerators is defined as K = qc / w. It is also known as Tcold / Thot - Tcold.

What happens to K reversible as Tc (temp cold) goes to 0k?

Sol:
K = Tcold/(Thot-Tcold)
K reversible means 1/K
Hence 1/K= (Thot-Tcold)/ Tcold
              = (Thot/ Tcold)-( Tcold/ Tcold)
         =  (Thot/ Tcold)- 1
By neglecting 1, which is a small value, we get
1/K directly proportional to 1/ Tcold

Hence as Tcold goes to 0k, K reversible tends to infinity, a very large value.

HomeWork Help: What is the current in the bulb..

Q) A 100 W lightbulb is plugged into a standard 120 V outlet. (a) How much does it
cost per 31-day month to leave the light turned continuously? Assume electrical
energy costs US$0.06/kWh. (b) What is the resistance of the bulb? (c) What is the current in the bulb?

Sol:
First let us find the energy used in 31 days is(in kWh) and then let go for calculating the cost.

a) U = P * t = 0.100kW * 31days * 24hrs/day
       = 74.4kWh
Cost per 31 day month = 74.4kW h * $0.06/kW h
  = $4.464
b) The resistance of the bulb is given by,
P = V2/R
R = V2/P
  = (120V)2/100W
=144Ω
c) The current in the bulb is given by,
P = VI
I = P/V
     = 100W/120V

 = 0.833 A

Saturday, 23 July 2011

TTH50015

What is the chemical reaction of fehling's test with sucrose?

Hint*: Fehling's test react with Sucrose - Chemistry


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TTH50014

Show how do identify system point for 0.003M phosphoric acid using graphical method and then plot the graph for the above result.

Hint*: PC -PH diagrams for triprotic acids

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